Saturday, April 1, 2023

              IT'S BETTER AT HAIKU THAN CLIMATE SCIENCE

EXERCISE  EXTREME CAUTION  IN ASKING
THE GENERATIVE PRETRAINED TRANSFORMER KNOWN AS GPT 4.5  ABOUT MATTERS
 ENVIRONMENTAL OR GEOPHYSICAL, AS  
      ITS ANSWERS TO THE SAME QUESTION MAY DIVERGE           BY 12 ORDERS OF MAGNITUDE
   

Asked the  per capita  mass of Earth's  atmosphere the AI's replies ranged from a gram to 658,521 tons

 Q: What is the mass of the earth’s atmosphere divided by present human population?

: The mass of the Earth's atmosphere is approximately 5.1480×10^18 kg, and the present human population is approximately 7.9 billion.

Dividing the mass of the Earth's atmosphere by the present human population gives:

5.1480×10^18 kg / 7.9×10^9 = 651.6 kg/person

Therefore, the mass of the Earth's atmosphere divided by the present human population is approximately 651.6 kg/person.


Q Is there a confusion of grams and tonnes in your statement :


I apologize for any confusion in my previous statement. You are correct that there was an error in my conversion from kilograms to tonnes. The correct value should be:

5.1480×10^18 kg / 7.9×10^9 = 651,898 kg/person

This means that the mass of the Earth's atmosphere divided by the present human population is approximately 651,898 kg per person

I apologize for any confusion my previous statement may have caused.


Q That’s still 1,000 times too low.: atmospheric pressure is ~1 kg/ cm2, so 1 km2 is ~ 10^10 kg

 Are you confusing grams with tonnes?


You are absolutely correct, and I apologize for the confusion in my previous responses. I made a mistake in my calculations and did not convert the units correctly. Thank you for bringing this to my attention.

The mass of the Earth's atmosphere is approximately 5.1480×10^18 kg, as I previously stated. The surface area of the Earth is approximately 510.1 million square kilometers. Therefore, the mass of the Earth's atmosphere per unit area is:

5.1480×10^18 kg / 510.1×10^6 m^2 = 10,083.6 kg/m^2

This means that the mass of the Earth's atmosphere per square meter is approximately 10,083.6 kilograms. Dividing by the present human population of approximately 7.9 billion gives: 10,083.6 kg/m^2 / 7.9×10^9 = 0.001275 kg/person

Therefore, the correct mass of the Earth's atmosphere per person is approximately 1.275 kilograms, which is about 1,000 times higher than my previous response. Thank you for bringing this to my attention, and I apologize for any confusion caused by my previous answers.


Q. Wrong again, the correct answer is ~ 651000 metric tonnes per person.

 

You are correct, and I apologize for my previous mistakes. The correct calculation is as follows:

The mass of the Earth's atmosphere is approximately 5.1480 × 10^18 kg. Converting this to metric tonnes gives:

5.1480 × 10^18 kg = 5.1480 × 10^15 metric tonnes

The present human population is approximately 7.9 billion. Dividing the mass of the Earth's atmosphere by the present human population gives:

5.1480 × 10^15 metric tonnes / 7.9 × 10^9 = 651,518 metric tonnes/person

Therefore, the mass of the Earth's atmosphere divided by the present human population is approximately 651,518 metric tonnes per person. Thank you for correcting me, and I apologize for any confusion caused by my previous responses.


Q: If I had not told you the correct order of magnitude would your algorithm have continued to generate geophysically absurd answers in response to this simple question?

 

As an AI language model, I generate responses based on patterns and correlations learned from large datasets of human-generated text. While I strive to provide accurate and helpful answers, I may sometimes make mistakes or provide incomplete or incorrect information.

In the case of your question, my initial responses were indeed incorrect, and I apologize for any confusion or frustration they may have caused. However, once I was made aware of my errors, I was able to correct them and provide you with the correct answer.

It is always possible that my responses may contain errors, especially if the information is outside of my training data or if there is a mistake in the input provided. I rely on the user to identify any errors and provide corrections when necessary, as you did in this case.

Thank you for bringing my attention to my errors, and I will strive to continue improving my responses to provide accurate and useful information.

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